Solve 3(2x-1)geq2(2x+3)

$$3 ( 2 x - 1 ) \geq 2 ( 2 x + 3 )$$

Solve for x

$$x\geq \frac{9}{2}$$

Solution Steps

Use the distributive property to multiply 3 by 2x-1.

$$6x-3\geq 2\left(2x+3\right)$$

Use the distributive property to multiply 2 by 2x+3.

$$6x-3\geq 4x+6$$

Subtract 4x from both sides.

$$6x-3-4x\geq 6$$

Combine 6x and -4x to get 2x.

$$2x-3\geq 6$$

Add 3 to both sides.

$$2x\geq 6+3$$

Add 6 and 3 to get 9.

$$2x\geq 9$$

Divide both sides by 2. Since 2 is positive, the inequality direction remains the same.

$$x\geq \frac{9}{2}$$