Solve 3(sqrt{3})^2+(sqrt{5})^2-2(sqrt{2})^2=

$$3 ( \sqrt { 3 } ) ^ { 2 } + ( \sqrt { 5 } ) ^ { 2 } - 2 ( \sqrt { 2 } ) ^ { 2 } =$$

Evaluate

$$10$$

Solution Steps

The square of \sqrt{3} is 3.

$$3\times 3+\left(\sqrt{5}\right)^{2}-2\left(\sqrt{2}\right)^{2}$$

Multiply 3 and 3 to get 9.

$$9+\left(\sqrt{5}\right)^{2}-2\left(\sqrt{2}\right)^{2}$$

The square of \sqrt{5} is 5.

$$9+5-2\left(\sqrt{2}\right)^{2}$$

Add 9 and 5 to get 14.

$$14-2\left(\sqrt{2}\right)^{2}$$

The square of \sqrt{2} is 2.

$$14-2\times 2$$

Multiply 2 and 2 to get 4.

$$14-4$$

Subtract 4 from 14 to get 10.

$$10$$

Factor

$$2\times 5$$