Solve 3(42+4y/5)=15

$$3 ( \frac { 42 + 4 y } { 5 } ) = 15$$

Solve for y

$$y = -\frac{17}{4} = -4\frac{1}{4} = -4.25$$

Steps for Solving Linear Equation

Divide both sides by 3.

$$\frac{42+4y}{5}=\frac{15}{3}$$

Divide 15 by 3 to get 5.

$$\frac{42+4y}{5}=5$$

Multiply both sides by 5.

$$42+4y=5\times 5$$

Multiply 5 and 5 to get 25.

$$42+4y=25$$

Subtract 42 from both sides.

$$4y=25-42$$

Subtract 42 from 25 to get -17.

$$4y=-17$$

Divide both sides by 4.

$$y=\frac{-17}{4}$$

Fraction \frac{-17}{4} can be rewritten as -\frac{17}{4} by extracting the negative sign.

$$y=-\frac{17}{4}$$