Solve 3(1/2)-3(1)-2x-6=

$$3 ( \frac { 1 } { 2 } ) - 3 ( 1 ) - 2 x - 6 =$$

Evaluate

$$-2x-\frac{15}{2}$$

Solution Steps

Multiply 3 and \frac{1}{2} to get \frac{3}{2}.

$$\frac{3}{2}-3\times 1-2x-6$$

Multiply 3 and 1 to get 3.

$$\frac{3}{2}-3-2x-6$$

Convert 3 to fraction \frac{6}{2}.

$$\frac{3}{2}-\frac{6}{2}-2x-6$$

Since \frac{3}{2} and \frac{6}{2} have the same denominator, subtract them by subtracting their numerators.

$$\frac{3-6}{2}-2x-6$$

Subtract 6 from 3 to get -3.

$$-\frac{3}{2}-2x-6$$

Convert 6 to fraction \frac{12}{2}.

$$-\frac{3}{2}-2x-\frac{12}{2}$$

Since -\frac{3}{2} and \frac{12}{2} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-3-12}{2}-2x$$

Subtract 12 from -3 to get -15.

$$-\frac{15}{2}-2x$$

Factor

$$\frac{-4x-15}{2}$$

Solution Steps

Factor out \frac{1}{2}.

$$\frac{-15-4x}{2}$$

Consider 3-6-4x-12. Multiply and combine like terms.

$$-4x-15$$

Rewrite the complete factored expression.

$$\frac{-4x-15}{2}$$