Solve 3x^2-9y+12=197

$$3 { x }^{ 2 } -9y+12 = 197$$

Solve for y

$$y=\frac{x^{2}}{3}-\frac{185}{9}$$

Steps for Solving Linear Equation

Subtract 3x^{2} from both sides.

$$-9y+12=197-3x^{2}$$

Subtract 12 from both sides.

$$-9y=197-3x^{2}-12$$

Subtract 12 from 197 to get 185.

$$-9y=185-3x^{2}$$

Divide both sides by -9.

$$\frac{-9y}{-9}=\frac{185-3x^{2}}{-9}$$

Dividing by -9 undoes the multiplication by -9.

$$y=\frac{185-3x^{2}}{-9}$$

Divide 185-3x^{2} by -9.

$$y=\frac{x^{2}}{3}-\frac{185}{9}$$

Solve for x (complex solution)

$$x=-\frac{\sqrt{27y+555}}{3}$$

$$x=\frac{\sqrt{27y+555}}{3}$$

Solve for x

$$x=\frac{\sqrt{27y+555}}{3}$$

$$x=-\frac{\sqrt{27y+555}}{3}\text{, }y\geq -\frac{185}{9}$$