Solve 3x^2-6x-2

$$3 { x }^{ 2 } -6x-2$$

Factor

$$3\left(x-\left(-\frac{\sqrt{15}}{3}+1\right)\right)\left(x-\left(\frac{\sqrt{15}}{3}+1\right)\right)$$

Steps Using the Quadratic Formula

Quadratic polynomial can be factored using the transformation ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), where x_{1} and x_{2} are the solutions of the quadratic equation ax^{2}+bx+c=0.

$$3x^{2}-6x-2=0$$

All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.

$$x=\frac{-\left(-6\right)±\sqrt{\left(-6\right)^{2}-4\times 3\left(-2\right)}}{2\times 3}$$

Square -6.

$$x=\frac{-\left(-6\right)±\sqrt{36-4\times 3\left(-2\right)}}{2\times 3}$$

Multiply -4 times 3.

$$x=\frac{-\left(-6\right)±\sqrt{36-12\left(-2\right)}}{2\times 3}$$

Multiply -12 times -2.

$$x=\frac{-\left(-6\right)±\sqrt{36+24}}{2\times 3}$$

Add 36 to 24.

$$x=\frac{-\left(-6\right)±\sqrt{60}}{2\times 3}$$

Take the square root of 60.

$$x=\frac{-\left(-6\right)±2\sqrt{15}}{2\times 3}$$

The opposite of -6 is 6.

$$x=\frac{6±2\sqrt{15}}{2\times 3}$$

Multiply 2 times 3.

$$x=\frac{6±2\sqrt{15}}{6}$$

Now solve the equation x=\frac{6±2\sqrt{15}}{6} when ± is plus. Add 6 to 2\sqrt{15}.

$$x=\frac{2\sqrt{15}+6}{6}$$

Divide 6+2\sqrt{15} by 6.

$$x=\frac{\sqrt{15}}{3}+1$$

Now solve the equation x=\frac{6±2\sqrt{15}}{6} when ± is minus. Subtract 2\sqrt{15} from 6.

$$x=\frac{6-2\sqrt{15}}{6}$$

Divide 6-2\sqrt{15} by 6.

$$x=-\frac{\sqrt{15}}{3}+1$$

Factor the original expression using ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right). Substitute 1+\frac{\sqrt{15}}{3} for x_{1} and 1-\frac{\sqrt{15}}{3} for x_{2}.

$$3x^{2}-6x-2=3\left(x-\left(\frac{\sqrt{15}}{3}+1\right)\right)\left(x-\left(-\frac{\sqrt{15}}{3}+1\right)\right)$$

Evaluate

$$3x^{2}-6x-2$$