Solve 3x^2-6x+2divx+1

$$3 { x }^{ 2 } -6x+2 \div x+1$$

Evaluate

$$3x^{2}-6x+1+\frac{2}{x}$$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Multiply 3x^{2}-6x+1 times \frac{x}{x}.

$$\frac{\left(3x^{2}-6x+1\right)x}{x}+\frac{2}{x}$$

Since \frac{\left(3x^{2}-6x+1\right)x}{x} and \frac{2}{x} have the same denominator, add them by adding their numerators.

$$\frac{\left(3x^{2}-6x+1\right)x+2}{x}$$

Do the multiplications in \left(3x^{2}-6x+1\right)x+2.

$$\frac{3x^{3}-6x^{2}+x+2}{x}$$

Factor

$$\frac{3\left(x-1\right)\left(x-\left(-\frac{\sqrt{33}}{6}+\frac{1}{2}\right)\right)\left(x-\left(\frac{\sqrt{33}}{6}+\frac{1}{2}\right)\right)}{x}$$