Solve for x
x\in \left(-\infty,-3\sqrt{2}\right)\cup \left(3\sqrt{2},\infty\right)
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3x^{2}-54>0
Multiply 6 and 9 to get 54.
x^{2}>18
Add 18 to both sides.
x^{2}>\left(3\sqrt{2}\right)^{2}
Calculate the square root of 18 and get 3\sqrt{2}. Rewrite 18 as \left(3\sqrt{2}\right)^{2}.
|x|>3\sqrt{2}
Inequality holds for |x|>3\sqrt{2}.
x<-3\sqrt{2}\text{; }x>3\sqrt{2}
Rewrite |x|>3\sqrt{2} as x<-3\sqrt{2}\text{; }x>3\sqrt{2}.
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