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3x^{2}-13x-12=0
Quadratic polynomial can be factored using the transformation ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), where x_{1} and x_{2} are the solutions of the quadratic equation ax^{2}+bx+c=0.
x=\frac{-\left(-13\right)±\sqrt{\left(-13\right)^{2}-4\times 3\left(-12\right)}}{2\times 3}
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
x=\frac{-\left(-13\right)±\sqrt{169-4\times 3\left(-12\right)}}{2\times 3}
Square -13.
x=\frac{-\left(-13\right)±\sqrt{169-12\left(-12\right)}}{2\times 3}
Multiply -4 times 3.
x=\frac{-\left(-13\right)±\sqrt{169+144}}{2\times 3}
Multiply -12 times -12.
x=\frac{-\left(-13\right)±\sqrt{313}}{2\times 3}
Add 169 to 144.
x=\frac{13±\sqrt{313}}{2\times 3}
The opposite of -13 is 13.
x=\frac{13±\sqrt{313}}{6}
Multiply 2 times 3.
x=\frac{\sqrt{313}+13}{6}
Now solve the equation x=\frac{13±\sqrt{313}}{6} when ± is plus. Add 13 to \sqrt{313}.
x=\frac{13-\sqrt{313}}{6}
Now solve the equation x=\frac{13±\sqrt{313}}{6} when ± is minus. Subtract \sqrt{313} from 13.
3x^{2}-13x-12=3\left(x-\frac{\sqrt{313}+13}{6}\right)\left(x-\frac{13-\sqrt{313}}{6}\right)
Factor the original expression using ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right). Substitute \frac{13+\sqrt{313}}{6} for x_{1} and \frac{13-\sqrt{313}}{6} for x_{2}.