Solve 3x^2=-9

$$3 { x }^{ 2 } =-9$$

Solve for x (complex solution)

$$x=-\sqrt{3}i\approx -0-1.732050808i$$

$$x=\sqrt{3}i\approx 1.732050808i$$

Steps by Finding Square Root

Divide both sides by 3.

$$x^{2}=\frac{-9}{3}$$

Divide -9 by 3 to get -3.

$$x^{2}=-3$$

The equation is now solved.

$$x=\sqrt{3}i x=-\sqrt{3}i$$

Steps Using the Quadratic Formula

Divide both sides by 3.

$$x^{2}=\frac{-9}{3}$$

Divide -9 by 3 to get -3.

$$x^{2}=-3$$

Add 3 to both sides.

$$x^{2}+3=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and 3 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\times 3}}{2}$$

Square 0.

$$x=\frac{0±\sqrt{-4\times 3}}{2}$$

Multiply -4 times 3.

$$x=\frac{0±\sqrt{-12}}{2}$$

Take the square root of -12.

$$x=\frac{0±2\sqrt{3}i}{2}$$

Now solve the equation x=\frac{0±2\sqrt{3}i}{2} when ± is plus.

$$x=\sqrt{3}i$$

Now solve the equation x=\frac{0±2\sqrt{3}i}{2} when ± is minus.

$$x=-\sqrt{3}i$$

The equation is now solved.

$$x=\sqrt{3}i x=-\sqrt{3}i$$