Solve 3x^2+2x-5-7x+x^2-1

$$3 { x }^{ 2 } +2x-5-7x+ { x }^{ 2 } -1$$

Evaluate

$$\left(x-2\right)\left(4x+3\right)$$

Solution Steps

Combine 2x and -7x to get -5x.

$$3x^{2}-5x-5+x^{2}-1$$

Combine 3x^{2} and x^{2} to get 4x^{2}.

$$4x^{2}-5x-5-1$$

Subtract 1 from -5 to get -6.

$$4x^{2}-5x-6$$

Factor

$$\left(x-2\right)\left(4x+3\right)$$

Solution Steps

Multiply and combine like terms.

$$4x^{2}-5x-6$$

Factor the expression by grouping. First, the expression needs to be rewritten as 4x^{2}+ax+bx-6. To find a and b, set up a system to be solved.

$$a+b=-5 ab=4\left(-6\right)=-24$$

Since ab is negative, a and b have the opposite signs. Since a+b is negative, the negative number has greater absolute value than the positive. List all such integer pairs that give product -24.

$$1,-24 2,-12 3,-8 4,-6$$

Calculate the sum for each pair.

$$1-24=-23 2-12=-10 3-8=-5 4-6=-2$$

The solution is the pair that gives sum -5.

$$a=-8 b=3$$

Rewrite 4x^{2}-5x-6 as \left(4x^{2}-8x\right)+\left(3x-6\right).

$$\left(4x^{2}-8x\right)+\left(3x-6\right)$$

Factor out 4x in the first and 3 in the second group.

$$4x\left(x-2\right)+3\left(x-2\right)$$

Factor out common term x-2 by using distributive property.

$$\left(x-2\right)\left(4x+3\right)$$