Solve 3*(2*-3)^2-4(3-2x)^2

$$3 \times ( 2 \times - 3 ) ^ { 2 } - 4 ( 3 - 2 x ) ^ { 2 }$$

Evaluate

$$-4\left(3-2x\right)^{2}+108$$

Solution Steps

Multiply 2 and -3 to get -6.

$$3\left(-6\right)^{2}-4\left(3-2x\right)^{2}$$

Calculate -6 to the power of 2 and get 36.

$$3\times 36-4\left(3-2x\right)^{2}$$

Multiply 3 and 36 to get 108.

$$108-4\left(3-2x\right)^{2}$$

Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(3-2x\right)^{2}.

$$108-4\left(9-12x+4x^{2}\right)$$

Use the distributive property to multiply -4 by 9-12x+4x^{2}.

$$108-36+48x-16x^{2}$$

Subtract 36 from 108 to get 72.

$$72+48x-16x^{2}$$

Expand

$$72+48x-16x^{2}$$

Solution Steps

Multiply 2 and -3 to get -6.

$$3\left(-6\right)^{2}-4\left(3-2x\right)^{2}$$

Calculate -6 to the power of 2 and get 36.

$$3\times 36-4\left(3-2x\right)^{2}$$

Multiply 3 and 36 to get 108.

$$108-4\left(3-2x\right)^{2}$$

Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(3-2x\right)^{2}.

$$108-4\left(9-12x+4x^{2}\right)$$

Use the distributive property to multiply -4 by 9-12x+4x^{2}.

$$108-36+48x-16x^{2}$$

Subtract 36 from 108 to get 72.

$$72+48x-16x^{2}$$