Solve 3*(-2)*2^2+8div4*3*2^2

$$3 \times ( - 2 ) \times 2 ^ { 2 } + 8 \div 4 \times 3 \times 2 ^ { 2 }$$

Evaluate

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Solution Steps

Multiply 3 and -2 to get -6.

$$-6\times 2^{2}+\frac{8}{4}\times 3\times 2^{2}$$

Calculate 2 to the power of 2 and get 4.

$$-6\times 4+\frac{8}{4}\times 3\times 2^{2}$$

Multiply -6 and 4 to get -24.

$$-24+\frac{8}{4}\times 3\times 2^{2}$$

Divide 8 by 4 to get 2.

$$-24+2\times 3\times 2^{2}$$

Multiply 2 and 3 to get 6.

$$-24+6\times 2^{2}$$

Calculate 2 to the power of 2 and get 4.

$$-24+6\times 4$$

Multiply 6 and 4 to get 24.

$$-24+24$$

Add -24 and 24 to get 0.

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Factor

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