Solve 3*2=30+x(x-3y)

$$3 \times 2=30+x(x-3y)$$

Solve for y

$$y=\frac{x}{3}+\frac{8}{x}$$

$$x\neq 0$$

Steps for Solving Linear Equation

Multiply 3 and 2 to get 6.

$$6=30+x\left(x-3y\right)$$

Use the distributive property to multiply x by x-3y.

$$6=30+x^{2}-3xy$$

Swap sides so that all variable terms are on the left hand side.

$$30+x^{2}-3xy=6$$

Subtract 30 from both sides.

$$x^{2}-3xy=6-30$$

Subtract 30 from 6 to get -24.

$$x^{2}-3xy=-24$$

Subtract x^{2} from both sides.

$$-3xy=-24-x^{2}$$

The equation is in standard form.

$$\left(-3x\right)y=-x^{2}-24$$

Divide both sides by -3x.

$$\frac{\left(-3x\right)y}{-3x}=\frac{-x^{2}-24}{-3x}$$

Dividing by -3x undoes the multiplication by -3x.

$$y=\frac{-x^{2}-24}{-3x}$$

Divide -24-x^{2} by -3x.

$$y=\frac{x}{3}+\frac{8}{x}$$

Solve for x (complex solution)

$$x=\frac{\sqrt{9y^{2}-96}+3y}{2}$$

$$x=\frac{-\sqrt{9y^{2}-96}+3y}{2}$$

Solve for x

$$x=\frac{\sqrt{9y^{2}-96}+3y}{2}$$

$$x=\frac{-\sqrt{9y^{2}-96}+3y}{2}\text{, }|y|\geq \frac{4\sqrt{6}}{3}$$