Solve 3sqrt{100-64}+sqrt{64+36}-7sqrt[3]{101}+25

$$3 \sqrt{ 100-64 } + \sqrt{ 64+36 } -7 \sqrt[ 3 ]{ 101 } +25$$

Evaluate

$$53-7\sqrt[3]{101}\approx 20.400933445$$

Solution Steps

Subtract 64 from 100 to get 36.

$$3\sqrt{36}+\sqrt{64+36}-7\sqrt[3]{101}+25$$

Calculate the square root of 36 and get 6.

$$3\times 6+\sqrt{64+36}-7\sqrt[3]{101}+25$$

Multiply 3 and 6 to get 18.

$$18+\sqrt{64+36}-7\sqrt[3]{101}+25$$

Add 64 and 36 to get 100.

$$18+\sqrt{100}-7\sqrt[3]{101}+25$$

Calculate the square root of 100 and get 10.

$$18+10-7\sqrt[3]{101}+25$$

Add 18 and 10 to get 28.

$$28-7\sqrt[3]{101}+25$$

Add 28 and 25 to get 53.

$$53-7\sqrt[3]{101}$$