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3\sqrt{3}-2\sqrt{2}+\sqrt{2}-27
Factor 8=2^{2}\times 2. Rewrite the square root of the product \sqrt{2^{2}\times 2} as the product of square roots \sqrt{2^{2}}\sqrt{2}. Take the square root of 2^{2}.
3\sqrt{3}-\sqrt{2}-27
Combine -2\sqrt{2} and \sqrt{2} to get -\sqrt{2}.