Solve 3sqrt{2x+1}=1

$$3 \sqrt { 2 x + 1 } = 1$$

Solve for x

$$x=-\frac{4}{9}\approx -0.444444444$$

Steps for Solving Radical Equations

Divide both sides by 3.

$$\frac{3\sqrt{2x+1}}{3}=\frac{1}{3}$$

Dividing by 3 undoes the multiplication by 3.

$$\sqrt{2x+1}=\frac{1}{3}$$

Square both sides of the equation.

$$2x+1=\frac{1}{9}$$

Subtract 1 from both sides of the equation.

$$2x+1-1=\frac{1}{9}-1$$

Subtracting 1 from itself leaves 0.

$$2x=\frac{1}{9}-1$$

Subtract 1 from \frac{1}{9}.

$$2x=-\frac{8}{9}$$

Divide both sides by 2.

$$\frac{2x}{2}=-\frac{\frac{8}{9}}{2}$$

Dividing by 2 undoes the multiplication by 2.

$$x=-\frac{\frac{8}{9}}{2}$$

Divide -\frac{8}{9} by 2.

$$x=-\frac{4}{9}$$