Solve 325/100-11/5

$$3 \frac{ 25 }{ 100 } -1 \frac{ 1 }{ 5 }$$

Evaluate

$$\frac{41}{20}=2.05$$

Solution Steps

Multiply 3 and 100 to get 300.

$$\frac{300+25}{100}-\frac{1\times 5+1}{5}$$

Add 300 and 25 to get 325.

$$\frac{325}{100}-\frac{1\times 5+1}{5}$$

Reduce the fraction \frac{325}{100} to lowest terms by extracting and canceling out 25.

$$\frac{13}{4}-\frac{1\times 5+1}{5}$$

Multiply 1 and 5 to get 5.

$$\frac{13}{4}-\frac{5+1}{5}$$

Add 5 and 1 to get 6.

$$\frac{13}{4}-\frac{6}{5}$$

Least common multiple of 4 and 5 is 20. Convert \frac{13}{4} and \frac{6}{5} to fractions with denominator 20.

$$\frac{65}{20}-\frac{24}{20}$$

Since \frac{65}{20} and \frac{24}{20} have the same denominator, subtract them by subtracting their numerators.

$$\frac{65-24}{20}$$

Subtract 24 from 65 to get 41.

$$\frac{41}{20}$$

Factor

$$\frac{41}{2 ^ {2} \cdot 5} = 2\frac{1}{20} = 2.05$$