Solve 37/9*7/10+7/10*32/9

$$3 \frac { 7 } { 9 } \times \frac { 7 } { 10 } + \frac { 7 } { 10 } \times 3 \frac { 2 } { 9 }$$

Evaluate

$$\frac{49}{10}=4.9$$

Solution Steps

Multiply 3 and 9 to get 27.

$$\frac{27+7}{9}\times \frac{7}{10}+\frac{7}{10}\times \frac{3\times 9+2}{9}$$

Add 27 and 7 to get 34.

$$\frac{34}{9}\times \frac{7}{10}+\frac{7}{10}\times \frac{3\times 9+2}{9}$$

Multiply \frac{34}{9} times \frac{7}{10} by multiplying numerator times numerator and denominator times denominator.

$$\frac{34\times 7}{9\times 10}+\frac{7}{10}\times \frac{3\times 9+2}{9}$$

Do the multiplications in the fraction \frac{34\times 7}{9\times 10}.

$$\frac{238}{90}+\frac{7}{10}\times \frac{3\times 9+2}{9}$$

Reduce the fraction \frac{238}{90} to lowest terms by extracting and canceling out 2.

$$\frac{119}{45}+\frac{7}{10}\times \frac{3\times 9+2}{9}$$

Multiply 3 and 9 to get 27.

$$\frac{119}{45}+\frac{7}{10}\times \frac{27+2}{9}$$

Add 27 and 2 to get 29.

$$\frac{119}{45}+\frac{7}{10}\times \frac{29}{9}$$

Multiply \frac{7}{10} times \frac{29}{9} by multiplying numerator times numerator and denominator times denominator.

$$\frac{119}{45}+\frac{7\times 29}{10\times 9}$$

Do the multiplications in the fraction \frac{7\times 29}{10\times 9}.

$$\frac{119}{45}+\frac{203}{90}$$

Least common multiple of 45 and 90 is 90. Convert \frac{119}{45} and \frac{203}{90} to fractions with denominator 90.

$$\frac{238}{90}+\frac{203}{90}$$

Since \frac{238}{90} and \frac{203}{90} have the same denominator, add them by adding their numerators.

$$\frac{238+203}{90}$$

Add 238 and 203 to get 441.

$$\frac{441}{90}$$

Reduce the fraction \frac{441}{90} to lowest terms by extracting and canceling out 9.

$$\frac{49}{10}$$

Factor

$$\frac{7 ^ {2}}{2 \cdot 5} = 4\frac{9}{10} = 4.9$$