Solve 37/10+41/4-63/8

$$3 \frac { 7 } { 10 } + 4 \frac { 1 } { 4 } - 6 \frac { 3 } { 8 }$$

Evaluate

$$\frac{63}{40}=1.575$$

Solution Steps

Multiply 3 and 10 to get 30.

$$\frac{30+7}{10}+\frac{4\times 4+1}{4}-\frac{6\times 8+3}{8}$$

Add 30 and 7 to get 37.

$$\frac{37}{10}+\frac{4\times 4+1}{4}-\frac{6\times 8+3}{8}$$

Multiply 4 and 4 to get 16.

$$\frac{37}{10}+\frac{16+1}{4}-\frac{6\times 8+3}{8}$$

Add 16 and 1 to get 17.

$$\frac{37}{10}+\frac{17}{4}-\frac{6\times 8+3}{8}$$

Least common multiple of 10 and 4 is 20. Convert \frac{37}{10} and \frac{17}{4} to fractions with denominator 20.

$$\frac{74}{20}+\frac{85}{20}-\frac{6\times 8+3}{8}$$

Since \frac{74}{20} and \frac{85}{20} have the same denominator, add them by adding their numerators.

$$\frac{74+85}{20}-\frac{6\times 8+3}{8}$$

Add 74 and 85 to get 159.

$$\frac{159}{20}-\frac{6\times 8+3}{8}$$

Multiply 6 and 8 to get 48.

$$\frac{159}{20}-\frac{48+3}{8}$$

Add 48 and 3 to get 51.

$$\frac{159}{20}-\frac{51}{8}$$

Least common multiple of 20 and 8 is 40. Convert \frac{159}{20} and \frac{51}{8} to fractions with denominator 40.

$$\frac{318}{40}-\frac{255}{40}$$

Since \frac{318}{40} and \frac{255}{40} have the same denominator, subtract them by subtracting their numerators.

$$\frac{318-255}{40}$$

Subtract 255 from 318 to get 63.

$$\frac{63}{40}$$

Factor

$$\frac{3 ^ {2} \cdot 7}{2 ^ {3} \cdot 5} = 1\frac{23}{40} = 1.575$$