Solve 33/x-3/4*21/5

$$3 \frac { 3 } { x } - \frac { 3 } { 4 } \times 2 \frac { 1 } { 5 }$$

Evaluate

$$-\frac{33}{20}+\frac{9}{x}$$

Short Solution Steps

Express 3\times \frac{3}{x} as a single fraction.

$$\frac{3\times 3}{x}-\frac{3}{4}\times \frac{2\times 5+1}{5}$$

Multiply 2 and 5 to get 10.

$$\frac{3\times 3}{x}-\frac{3}{4}\times \frac{10+1}{5}$$

Add 10 and 1 to get 11.

$$\frac{3\times 3}{x}-\frac{3}{4}\times \frac{11}{5}$$

Multiply \frac{3}{4} times \frac{11}{5} by multiplying numerator times numerator and denominator times denominator.

$$\frac{3\times 3}{x}-\frac{3\times 11}{4\times 5}$$

Do the multiplications in the fraction \frac{3\times 11}{4\times 5}.

$$\frac{3\times 3}{x}-\frac{33}{20}$$

To add or subtract expressions, expand them to make their denominators the same. Least common multiple of x and 20 is 20x. Multiply \frac{3\times 3}{x} times \frac{20}{20}. Multiply \frac{33}{20} times \frac{x}{x}.

$$\frac{20\times 3\times 3}{20x}-\frac{33x}{20x}$$

Since \frac{20\times 3\times 3}{20x} and \frac{33x}{20x} have the same denominator, subtract them by subtracting their numerators.

$$\frac{20\times 3\times 3-33x}{20x}$$

Do the multiplications in 20\times 3\times 3-33x.

$$\frac{180-33x}{20x}$$

Expand

$$-\frac{33}{20}+\frac{9}{x}$$

Short Solution Steps

Express 3\times \frac{3}{x} as a single fraction.

$$\frac{3\times 3}{x}-\frac{3}{4}\times \frac{2\times 5+1}{5}$$

Multiply 2 and 5 to get 10.

$$\frac{3\times 3}{x}-\frac{3}{4}\times \frac{10+1}{5}$$

Add 10 and 1 to get 11.

$$\frac{3\times 3}{x}-\frac{3}{4}\times \frac{11}{5}$$

Multiply \frac{3}{4} times \frac{11}{5} by multiplying numerator times numerator and denominator times denominator.

$$\frac{3\times 3}{x}-\frac{3\times 11}{4\times 5}$$

Do the multiplications in the fraction \frac{3\times 11}{4\times 5}.

$$\frac{3\times 3}{x}-\frac{33}{20}$$

To add or subtract expressions, expand them to make their denominators the same. Least common multiple of x and 20 is 20x. Multiply \frac{3\times 3}{x} times \frac{20}{20}. Multiply \frac{33}{20} times \frac{x}{x}.

$$\frac{20\times 3\times 3}{20x}-\frac{33x}{20x}$$

Since \frac{20\times 3\times 3}{20x} and \frac{33x}{20x} have the same denominator, subtract them by subtracting their numerators.

$$\frac{20\times 3\times 3-33x}{20x}$$

Do the multiplications in 20\times 3\times 3-33x.

$$\frac{180-33x}{20x}$$