Solve 33/7div27/28

$$3 \frac { 3 } { 7 } \div \frac { 27 } { 28 }$$

Evaluate

$$\frac{32}{9}\approx 3.555555556$$

Solution Steps

Divide \frac{3\times 7+3}{7} by \frac{27}{28} by multiplying \frac{3\times 7+3}{7} by the reciprocal of \frac{27}{28}.

$$\frac{\left(3\times 7+3\right)\times 28}{7\times 27}$$

Cancel out 7 in both numerator and denominator.

$$\frac{4\left(3+3\times 7\right)}{27}$$

Multiply 3 and 7 to get 21.

$$\frac{4\left(3+21\right)}{27}$$

Add 3 and 21 to get 24.

$$\frac{4\times 24}{27}$$

Multiply 4 and 24 to get 96.

$$\frac{96}{27}$$

Reduce the fraction \frac{96}{27} to lowest terms by extracting and canceling out 3.

$$\frac{32}{9}$$

Factor

$$\frac{2 ^ {5}}{3 ^ {2}} = 3\frac{5}{9} = 3.5555555555555554$$