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\frac{\left(3\times 2+3\right)\times 7}{2\left(1\times 7+1\right)}
Divide \frac{3\times 2+3}{2} by \frac{1\times 7+1}{7} by multiplying \frac{3\times 2+3}{2} by the reciprocal of \frac{1\times 7+1}{7}.
\frac{\left(6+3\right)\times 7}{2\left(1\times 7+1\right)}
Multiply 3 and 2 to get 6.
\frac{9\times 7}{2\left(1\times 7+1\right)}
Add 6 and 3 to get 9.
\frac{63}{2\left(1\times 7+1\right)}
Multiply 9 and 7 to get 63.
\frac{63}{2\left(7+1\right)}
Multiply 1 and 7 to get 7.
\frac{63}{2\times 8}
Add 7 and 1 to get 8.
\frac{63}{16}
Multiply 2 and 8 to get 16.