Solve 33/14div21/7=

$$3 \frac { 3 } { 14 } \div 2 \frac { 1 } { 7 } =$$

Evaluate

$$\frac{3}{2}=1.5$$

Solution Steps

Divide \frac{3\times 14+3}{14} by \frac{2\times 7+1}{7} by multiplying \frac{3\times 14+3}{14} by the reciprocal of \frac{2\times 7+1}{7}.

$$\frac{\left(3\times 14+3\right)\times 7}{14\left(2\times 7+1\right)}$$

Cancel out 7 in both numerator and denominator.

$$\frac{3+3\times 14}{2\left(1+2\times 7\right)}$$

Multiply 3 and 14 to get 42.

$$\frac{3+42}{2\left(1+2\times 7\right)}$$

Add 3 and 42 to get 45.

$$\frac{45}{2\left(1+2\times 7\right)}$$

Multiply 2 and 7 to get 14.

$$\frac{45}{2\left(1+14\right)}$$

Add 1 and 14 to get 15.

$$\frac{45}{2\times 15}$$

Multiply 2 and 15 to get 30.

$$\frac{45}{30}$$

Reduce the fraction \frac{45}{30} to lowest terms by extracting and canceling out 15.

$$\frac{3}{2}$$

Factor

$$\frac{3}{2} = 1\frac{1}{2} = 1.5$$