Solve 31/6div12/3

$$3 \frac { 1 } { 6 } \div 1 \frac { 2 } { 3 }$$

Evaluate

$$\frac{19}{10}=1.9$$

Solution Steps

Divide \frac{3\times 6+1}{6} by \frac{1\times 3+2}{3} by multiplying \frac{3\times 6+1}{6} by the reciprocal of \frac{1\times 3+2}{3}.

$$\frac{\left(3\times 6+1\right)\times 3}{6\left(1\times 3+2\right)}$$

Cancel out 3 in both numerator and denominator.

$$\frac{1+3\times 6}{2\left(2+3\right)}$$

Multiply 3 and 6 to get 18.

$$\frac{1+18}{2\left(2+3\right)}$$

Add 1 and 18 to get 19.

$$\frac{19}{2\left(2+3\right)}$$

Add 2 and 3 to get 5.

$$\frac{19}{2\times 5}$$

Multiply 2 and 5 to get 10.

$$\frac{19}{10}$$

Factor

$$\frac{19}{2 \cdot 5} = 1\frac{9}{10} = 1.9$$