Solve 31/2:49/4*7/8=

$$3 \frac { 1 } { 2 } : \frac { 49 } { 4 } \cdot \frac { 7 } { 8 } =$$

Evaluate

$$\frac{1}{4}=0.25$$

Solution Steps

Divide \frac{3\times 2+1}{2} by \frac{49}{4} by multiplying \frac{3\times 2+1}{2} by the reciprocal of \frac{49}{4}.

$$\frac{\left(3\times 2+1\right)\times 4}{2\times 49}\times \frac{7}{8}$$

Cancel out 2 in both numerator and denominator.

$$\frac{2\left(1+2\times 3\right)}{49}\times \frac{7}{8}$$

Multiply 2 and 3 to get 6.

$$\frac{2\left(1+6\right)}{49}\times \frac{7}{8}$$

Add 1 and 6 to get 7.

$$\frac{2\times 7}{49}\times \frac{7}{8}$$

Multiply 2 and 7 to get 14.

$$\frac{14}{49}\times \frac{7}{8}$$

Reduce the fraction \frac{14}{49} to lowest terms by extracting and canceling out 7.

$$\frac{2}{7}\times \frac{7}{8}$$

Multiply \frac{2}{7} times \frac{7}{8} by multiplying numerator times numerator and denominator times denominator.

$$\frac{2\times 7}{7\times 8}$$

Cancel out 7 in both numerator and denominator.

$$\frac{2}{8}$$

Reduce the fraction \frac{2}{8} to lowest terms by extracting and canceling out 2.

$$\frac{1}{4}$$

Factor

$$\frac{1}{2 ^ {2}} = 0.25$$