Solve 3-2x/4-x+1xgeq2

$$3 \frac { - 2 x } { 4 } - x + 1 x \geq 2$$

Solve for x

$$x\leq -\frac{4}{3}$$

Solution Steps

Multiply both sides of the equation by 4. Since 4 is positive, the inequality direction remains the same.

$$3\left(-2\right)x-4x+4x\geq 8$$

Multiply 3 and -2 to get -6.

$$-6x-4x+4x\geq 8$$

Combine -6x and -4x to get -10x.

$$-10x+4x\geq 8$$

Combine -10x and 4x to get -6x.

$$-6x\geq 8$$

Divide both sides by -6. Since -6 is negative, the inequality direction is changed.

$$x\leq \frac{8}{-6}$$

Reduce the fraction \frac{8}{-6} to lowest terms by extracting and canceling out 2.

$$x\leq -\frac{4}{3}$$