Solve 3*8^2+6*5^2-3*7^2=

$$3 \cdot 8 ^ { 2 } + 6 \cdot 5 ^ { 2 } - 3 \cdot 7 ^ { 2 } =$$

Evaluate

$$195$$

Solution Steps

Calculate 8 to the power of 2 and get 64.

$$3\times 64+6\times 5^{2}-3\times 7^{2}$$

Multiply 3 and 64 to get 192.

$$192+6\times 5^{2}-3\times 7^{2}$$

Calculate 5 to the power of 2 and get 25.

$$192+6\times 25-3\times 7^{2}$$

Multiply 6 and 25 to get 150.

$$192+150-3\times 7^{2}$$

Add 192 and 150 to get 342.

$$342-3\times 7^{2}$$

Calculate 7 to the power of 2 and get 49.

$$342-3\times 49$$

Multiply 3 and 49 to get 147.

$$342-147$$

Subtract 147 from 342 to get 195.

$$195$$

Factor

$$3\times 5\times 13$$