Solve 3*(-18/9)^2-5*(-18/9)+2=0

$$3 \cdot ( - \frac { 18 } { 9 } ) ^ { 2 } - 5 \cdot ( - \frac { 18 } { 9 } ) + 2 = 0$$

Verify

Solution Steps

Divide 18 by 9 to get 2.

$$3\left(-2\right)^{2}-5\left(-\frac{18}{9}\right)+2=0$$

Calculate -2 to the power of 2 and get 4.

$$3\times 4-5\left(-\frac{18}{9}\right)+2=0$$

Multiply 3 and 4 to get 12.

$$12-5\left(-\frac{18}{9}\right)+2=0$$

Divide 18 by 9 to get 2.

$$12-5\left(-2\right)+2=0$$

Multiply 5 and -2 to get -10.

$$12-\left(-10\right)+2=0$$

The opposite of -10 is 10.

$$12+10+2=0$$

Add 12 and 10 to get 22.

$$22+2=0$$

Add 22 and 2 to get 24.

$$24=0$$

Compare 24 and 0.

$$\text{false}$$