Solve 3{2+5[3+(6-4)^2+1]-7}

$$3 \{ 2 + 5 [ 3 + ( 6 - 4 ) ^ { 2 } + 1 ] - 7 \}$$

Evaluate

$$105$$

Solution Steps

Subtract 4 from 6 to get 2.

$$3\left(2+5\left(3+2^{2}+1\right)-7\right)$$

Calculate 2 to the power of 2 and get 4.

$$3\left(2+5\left(3+4+1\right)-7\right)$$

Add 3 and 4 to get 7.

$$3\left(2+5\left(7+1\right)-7\right)$$

Add 7 and 1 to get 8.

$$3\left(2+5\times 8-7\right)$$

Multiply 5 and 8 to get 40.

$$3\left(2+40-7\right)$$

Add 2 and 40 to get 42.

$$3\left(42-7\right)$$

Subtract 7 from 42 to get 35.

$$3\times 35$$

Multiply 3 and 35 to get 105.

$$105$$

Factor

$$3\times 5\times 7$$