Solve 3^2-7*2-sqrt{49}+(2-5^2)=

$$3 ^ { 2 } - 7 \cdot 2 - \sqrt { 49 } + ( 2 - 5 ^ { 2 } ) =$$

Evaluate

$$-35$$

Solution Steps

Calculate 3 to the power of 2 and get 9.

$$9-7\times 2-\sqrt{49}+2-5^{2}$$

Multiply 7 and 2 to get 14.

$$9-14-\sqrt{49}+2-5^{2}$$

Subtract 14 from 9 to get -5.

$$-5-\sqrt{49}+2-5^{2}$$

Calculate the square root of 49 and get 7.

$$-5-7+2-5^{2}$$

Subtract 7 from -5 to get -12.

$$-12+2-5^{2}$$

Calculate 5 to the power of 2 and get 25.

$$-12+2-25$$

Subtract 25 from 2 to get -23.

$$-12-23$$

Subtract 23 from -12 to get -35.

$$-35$$

Factor

$$-35$$