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\frac{1}{27}\times 3^{-q}=81
Use the rules of exponents and logarithms to solve the equation.
3^{-q}=2187
Multiply both sides by 27.
\log(3^{-q})=\log(2187)
Take the logarithm of both sides of the equation.
-q\log(3)=\log(2187)
The logarithm of a number raised to a power is the power times the logarithm of the number.
-q=\frac{\log(2187)}{\log(3)}
Divide both sides by \log(3).
-q=\log_{3}\left(2187\right)
By the change-of-base formula \frac{\log(a)}{\log(b)}=\log_{b}\left(a\right).
q=\frac{7}{-1}
Divide both sides by -1.