Solve 3^-3*27^2*(9^4)^-5=

$$3 ^ { - 3 } \cdot 27 ^ { 2 } \cdot ( 9 ^ { 4 } ) ^ { - 5 } =$$

Evaluate

$$\frac{1}{450283905890997363}\approx 2.220821102 \cdot 10^{-18}$$

Solution Steps

To raise a power to another power, multiply the exponents. Multiply 4 and -5 to get -20.

$$3^{-3}\times 27^{2}\times 9^{-20}$$

Calculate 3 to the power of -3 and get \frac{1}{27}.

$$\frac{1}{27}\times 27^{2}\times 9^{-20}$$

Calculate 27 to the power of 2 and get 729.

$$\frac{1}{27}\times 729\times 9^{-20}$$

Multiply \frac{1}{27} and 729 to get 27.

$$27\times 9^{-20}$$

Calculate 9 to the power of -20 and get \frac{1}{12157665459056928801}.

$$27\times \frac{1}{12157665459056928801}$$

Multiply 27 and \frac{1}{12157665459056928801} to get \frac{1}{450283905890997363}.

$$\frac{1}{450283905890997363}$$

Factor

$$\frac{1}{3 ^ {37}} = 2.220821101791889 \times 10^{-18}$$