Solve 3[(7-5)^2+(19-20)^2]+14

$$3 [ ( 7 - 5 ) ^ { 2 } + ( 19 - 20 ) ^ { 2 } ] + 14$$

Evaluate

$$29$$

Solution Steps

Subtract 5 from 7 to get 2.

$$3\left(2^{2}+\left(19-20\right)^{2}\right)+14$$

Calculate 2 to the power of 2 and get 4.

$$3\left(4+\left(19-20\right)^{2}\right)+14$$

Subtract 20 from 19 to get -1.

$$3\left(4+\left(-1\right)^{2}\right)+14$$

Calculate -1 to the power of 2 and get 1.

$$3\left(4+1\right)+14$$

Add 4 and 1 to get 5.

$$3\times 5+14$$

Multiply 3 and 5 to get 15.

$$15+14$$

Add 15 and 14 to get 29.

$$29$$

Factor

$$29$$