Solve 3/3+(4/3)^2-2^4

$$3 / 3 + ( \frac { 4 } { 3 } ) ^ { 2 } - 2 ^ { 4 }$$

Evaluate

$$-\frac{119}{9}\approx -13.222222222$$

Solution Steps

Divide 3 by 3 to get 1.

$$1+\left(\frac{4}{3}\right)^{2}-2^{4}$$

Calculate \frac{4}{3} to the power of 2 and get \frac{16}{9}.

$$1+\frac{16}{9}-2^{4}$$

Convert 1 to fraction \frac{9}{9}.

$$\frac{9}{9}+\frac{16}{9}-2^{4}$$

Since \frac{9}{9} and \frac{16}{9} have the same denominator, add them by adding their numerators.

$$\frac{9+16}{9}-2^{4}$$

Add 9 and 16 to get 25.

$$\frac{25}{9}-2^{4}$$

Calculate 2 to the power of 4 and get 16.

$$\frac{25}{9}-16$$

Convert 16 to fraction \frac{144}{9}.

$$\frac{25}{9}-\frac{144}{9}$$

Since \frac{25}{9} and \frac{144}{9} have the same denominator, subtract them by subtracting their numerators.

$$\frac{25-144}{9}$$

Subtract 144 from 25 to get -119.

$$-\frac{119}{9}$$

Factor

$$-\frac{119}{9} = -13\frac{2}{9} = -13.222222222222221$$