Solve 3+(9-x)^2=x^2

$$3 + ( 9 - x ) ^ { 2 } = x ^ { 2 }$$

Solve for x

$$x = \frac{14}{3} = 4\frac{2}{3} \approx 4.666666667$$

Steps for Solving Linear Equation

Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(9-x\right)^{2}.

$$3+81-18x+x^{2}=x^{2}$$

Add 3 and 81 to get 84.

$$84-18x+x^{2}=x^{2}$$

Subtract x^{2} from both sides.

$$84-18x+x^{2}-x^{2}=0$$

Combine x^{2} and -x^{2} to get 0.

$$84-18x=0$$

Subtract 84 from both sides. Anything subtracted from zero gives its negation.

$$-18x=-84$$

Divide both sides by -18.

$$x=\frac{-84}{-18}$$

Reduce the fraction \frac{-84}{-18} to lowest terms by extracting and canceling out -6.

$$x=\frac{14}{3}$$