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\left(y+z-3-x\right)\left(y+z+3+x\right)
Rewrite 2yz-x^{2}-9+z^{2}+y^{2}-6x as \left(y+z\right)^{2}-\left(3+x\right)^{2}. The difference of squares can be factored using the rule: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).
\left(-x+y+z-3\right)\left(x+y+z+3\right)
Reorder the terms.