Solve 2y-3x+6=0

$$2y-3x+6=0$$

Solve for x

$$x=\frac{2\left(y+3\right)}{3}$$

Steps for Solving Linear Equation

Subtract 2y from both sides. Anything subtracted from zero gives its negation.

$$-3x+6=-2y$$

Subtract 6 from both sides.

$$-3x=-2y-6$$

Divide both sides by -3.

$$\frac{-3x}{-3}=\frac{-2y-6}{-3}$$

Dividing by -3 undoes the multiplication by -3.

$$x=\frac{-2y-6}{-3}$$

Divide -2y-6 by -3.

$$x=\frac{2y}{3}+2$$

Solve for y

$$y=\frac{3\left(x-2\right)}{2}$$

Steps for Solving Linear Equation

Add 3x to both sides. Anything plus zero gives itself.

$$2y+6=3x$$

Subtract 6 from both sides.

$$2y=3x-6$$

Divide both sides by 2.

$$\frac{2y}{2}=\frac{3x-6}{2}$$

Dividing by 2 undoes the multiplication by 2.

$$y=\frac{3x-6}{2}$$

Divide -6+3x by 2.

$$y=\frac{3x}{2}-3$$