Solve for x
x=-\frac{3}{2}+\frac{5}{2y}
y\neq 0
Solve for y
y=\frac{5}{2x+3}
x\neq -\frac{3}{2}
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2yx=5-3y
The equation is in standard form.
\frac{2yx}{2y}=\frac{5-3y}{2y}
Divide both sides by 2y.
x=\frac{5-3y}{2y}
Dividing by 2y undoes the multiplication by 2y.
x=-\frac{3}{2}+\frac{5}{2y}
Divide 5-3y by 2y.
2xy+3y=5
Add 3y to both sides.
\left(2x+3\right)y=5
Combine all terms containing y.
\frac{\left(2x+3\right)y}{2x+3}=\frac{5}{2x+3}
Divide both sides by 2x+3.
y=\frac{5}{2x+3}
Dividing by 2x+3 undoes the multiplication by 2x+3.
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