Solve 2x3x=7-3x

$$2x3x=7-3x$$

Solve for x

$$x=\frac{7}{2x_{3}+3}$$

$$x_{3}\neq -\frac{3}{2}$$

Steps for Solving Linear Equation

Add 3x to both sides.

$$2x_{3}x+3x=7$$

Combine all terms containing x.

$$\left(2x_{3}+3\right)x=7$$

Divide both sides by 2x_{3}+3.

$$\frac{\left(2x_{3}+3\right)x}{2x_{3}+3}=\frac{7}{2x_{3}+3}$$

Dividing by 2x_{3}+3 undoes the multiplication by 2x_{3}+3.

$$x=\frac{7}{2x_{3}+3}$$

Solve for x_3

$$x_{3}=-\frac{3}{2}+\frac{7}{2x}$$

$$x\neq 0$$

Steps for Solving Linear Equation

The equation is in standard form.

$$2xx_{3}=7-3x$$

Divide both sides by 2x.

$$\frac{2xx_{3}}{2x}=\frac{7-3x}{2x}$$

Dividing by 2x undoes the multiplication by 2x.

$$x_{3}=\frac{7-3x}{2x}$$

Divide 7-3x by 2x.

$$x_{3}=-\frac{3}{2}+\frac{7}{2x}$$