Solve 2x-8geq9x-10

$$2x-8 \geq 9x-10$$

Solve for x

$$x\leq \frac{2}{7}$$

Solution Steps

Subtract 9x from both sides.

$$2x-8-9x\geq -10$$

Combine 2x and -9x to get -7x.

$$-7x-8\geq -10$$

Add 8 to both sides.

$$-7x\geq -10+8$$

Add -10 and 8 to get -2.

$$-7x\geq -2$$

Divide both sides by -7. Since -7 is negative, the inequality direction is changed.

$$x\leq \frac{-2}{-7}$$

Fraction \frac{-2}{-7} can be simplified to \frac{2}{7} by removing the negative sign from both the numerator and the denominator.

$$x\leq \frac{2}{7}$$