Solve 2x-6*16^2+56x+49

$$2x-6 \times { 16 }^{ 2 } +56x+49$$

Evaluate

$$58x-1487$$

Solution Steps

Calculate 16 to the power of 2 and get 256.

$$2x-6\times 256+56x+49$$

Multiply 6 and 256 to get 1536.

$$2x-1536+56x+49$$

Combine 2x and 56x to get 58x.

$$58x-1536+49$$

Add -1536 and 49 to get -1487.

$$58x-1487$$

Differentiate w.r.t. x

$$58$$

Steps Using Derivative Rule for Sum

Calculate 16 to the power of 2 and get 256.

$$\frac{\mathrm{d}}{\mathrm{d}x}(2x-6\times 256+56x+49)$$

Multiply 6 and 256 to get 1536.

$$\frac{\mathrm{d}}{\mathrm{d}x}(2x-1536+56x+49)$$

Combine 2x and 56x to get 58x.

$$\frac{\mathrm{d}}{\mathrm{d}x}(58x-1536+49)$$

Add -1536 and 49 to get -1487.

$$\frac{\mathrm{d}}{\mathrm{d}x}(58x-1487)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$58x^{1-1}$$

Subtract 1 from 1.

$$58x^{0}$$

For any term t except 0, t^{0}=1.

$$58\times 1$$

For any term t, t\times 1=t and 1t=t.

$$58$$