Solve 2x-4y+80=0

$$2x-4y+80 = 0$$

Solve for x

$$x=2\left(y-20\right)$$

Steps for Solving Linear Equation

Add 4y to both sides. Anything plus zero gives itself.

$$2x+80=4y$$

Subtract 80 from both sides.

$$2x=4y-80$$

Divide both sides by 2.

$$\frac{2x}{2}=\frac{4y-80}{2}$$

Dividing by 2 undoes the multiplication by 2.

$$x=\frac{4y-80}{2}$$

Divide -80+4y by 2.

$$x=2y-40$$

Solve for y

$$y=\frac{x+40}{2}$$

Steps for Solving Linear Equation

Subtract 2x from both sides. Anything subtracted from zero gives its negation.

$$-4y+80=-2x$$

Subtract 80 from both sides.

$$-4y=-2x-80$$

Divide both sides by -4.

$$\frac{-4y}{-4}=\frac{-2x-80}{-4}$$

Dividing by -4 undoes the multiplication by -4.

$$y=\frac{-2x-80}{-4}$$

Divide -2x-80 by -4.

$$y=\frac{x}{2}+20$$