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2x+8=3y
Add 3y to both sides. Anything plus zero gives itself.
2x=3y-8
Subtract 8 from both sides.
\frac{2x}{2}=\frac{3y-8}{2}
Divide both sides by 2.
x=\frac{3y-8}{2}
Dividing by 2 undoes the multiplication by 2.
x=\frac{3y}{2}-4
Divide 3y-8 by 2.
-3y+8=-2x
Subtract 2x from both sides. Anything subtracted from zero gives its negation.
-3y=-2x-8
Subtract 8 from both sides.
\frac{-3y}{-3}=\frac{-2x-8}{-3}
Divide both sides by -3.
y=\frac{-2x-8}{-3}
Dividing by -3 undoes the multiplication by -3.
y=\frac{2x+8}{3}
Divide -2x-8 by -3.