Solve 2x(x-3)-3(x-1)=2x^2+15

$$2x(x-3)-3(x-1)=2 { x }^{ 2 } +15$$

Solve for x

$$x = -\frac{4}{3} = -1\frac{1}{3} \approx -1.333333333$$

Steps for Solving Linear Equation

Use the distributive property to multiply 2x by x-3.

$$2x^{2}-6x-3\left(x-1\right)=2x^{2}+15$$

Use the distributive property to multiply -3 by x-1.

$$2x^{2}-6x-3x+3=2x^{2}+15$$

Combine -6x and -3x to get -9x.

$$2x^{2}-9x+3=2x^{2}+15$$

Subtract 2x^{2} from both sides.

$$2x^{2}-9x+3-2x^{2}=15$$

Combine 2x^{2} and -2x^{2} to get 0.

$$-9x+3=15$$

Subtract 3 from both sides.

$$-9x=15-3$$

Subtract 3 from 15 to get 12.

$$-9x=12$$

Divide both sides by -9.

$$x=\frac{12}{-9}$$

Reduce the fraction \frac{12}{-9} to lowest terms by extracting and canceling out 3.

$$x=-\frac{4}{3}$$