Solve 2x+4y-62=x+y-23

$$2x+4y-62=x+y-23$$

Solve for x

$$x=39-3y$$

Solution Steps

Subtract x from both sides.

$$2x+4y-62-x=y-23$$

Combine 2x and -x to get x.

$$x+4y-62=y-23$$

Subtract 4y from both sides.

$$x-62=y-23-4y$$

Combine y and -4y to get -3y.

$$x-62=-3y-23$$

Add 62 to both sides.

$$x=-3y-23+62$$

Add -23 and 62 to get 39.

$$x=-3y+39$$

Solve for y

$$y=-\frac{x}{3}+13$$

Steps for Solving Linear Equation

Subtract y from both sides.

$$2x+4y-62-y=x-23$$

Combine 4y and -y to get 3y.

$$2x+3y-62=x-23$$

Subtract 2x from both sides.

$$3y-62=x-23-2x$$

Combine x and -2x to get -x.

$$3y-62=-x-23$$

Add 62 to both sides.

$$3y=-x-23+62$$

Add -23 and 62 to get 39.

$$3y=-x+39$$

The equation is in standard form.

$$3y=39-x$$

Divide both sides by 3.

$$\frac{3y}{3}=\frac{39-x}{3}$$

Dividing by 3 undoes the multiplication by 3.

$$y=\frac{39-x}{3}$$

Divide -x+39 by 3.

$$y=-\frac{x}{3}+13$$