Solve for x
x=\frac{-3y-3}{2}
Solve for y
y=-\frac{2x}{3}-1
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2x=-3-3y
Subtract 3y from both sides.
2x=-3y-3
The equation is in standard form.
\frac{2x}{2}=\frac{-3y-3}{2}
Divide both sides by 2.
x=\frac{-3y-3}{2}
Dividing by 2 undoes the multiplication by 2.
3y=-3-2x
Subtract 2x from both sides.
3y=-2x-3
The equation is in standard form.
\frac{3y}{3}=\frac{-2x-3}{3}
Divide both sides by 3.
y=\frac{-2x-3}{3}
Dividing by 3 undoes the multiplication by 3.
y=-\frac{2x}{3}-1
Divide -3-2x by 3.
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