Solve for x
x=-\frac{z}{2}-\frac{3y}{2}+3
Solve for y
y=-\frac{z}{3}-\frac{2x}{3}+2
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2x+z=6-3y
Subtract 3y from both sides.
2x=6-3y-z
Subtract z from both sides.
2x=6-z-3y
The equation is in standard form.
\frac{2x}{2}=\frac{6-z-3y}{2}
Divide both sides by 2.
x=\frac{6-z-3y}{2}
Dividing by 2 undoes the multiplication by 2.
x=-\frac{z}{2}-\frac{3y}{2}+3
Divide 6-3y-z by 2.
3y+z=6-2x
Subtract 2x from both sides.
3y=6-2x-z
Subtract z from both sides.
3y=6-z-2x
The equation is in standard form.
\frac{3y}{3}=\frac{6-z-2x}{3}
Divide both sides by 3.
y=\frac{6-z-2x}{3}
Dividing by 3 undoes the multiplication by 3.
y=-\frac{z}{3}-\frac{2x}{3}+2
Divide 6-2x-z by 3.
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