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2x+3=0+\frac{\sqrt{5}}{\sqrt{53}}
Rewrite the square root of the division \sqrt{\frac{5}{53}} as the division of square roots \frac{\sqrt{5}}{\sqrt{53}}.
2x+3=0+\frac{\sqrt{5}\sqrt{53}}{\left(\sqrt{53}\right)^{2}}
Rationalize the denominator of \frac{\sqrt{5}}{\sqrt{53}} by multiplying numerator and denominator by \sqrt{53}.
2x+3=0+\frac{\sqrt{5}\sqrt{53}}{53}
The square of \sqrt{53} is 53.
2x+3=0+\frac{\sqrt{265}}{53}
To multiply \sqrt{5} and \sqrt{53}, multiply the numbers under the square root.
2x+3=\frac{\sqrt{265}}{53}
Anything plus zero gives itself.
2x=\frac{\sqrt{265}}{53}-3
Subtract 3 from both sides.
106x=\sqrt{265}-159
Multiply both sides of the equation by 53.
\frac{106x}{106}=\frac{\sqrt{265}-159}{106}
Divide both sides by 106.
x=\frac{\sqrt{265}-159}{106}
Dividing by 106 undoes the multiplication by 106.
x=\frac{\sqrt{265}}{106}-\frac{3}{2}
Divide \sqrt{265}-159 by 106.