Solve 2x*4x+2=0

$$2x \times 4x+2=0$$

Solve for x (complex solution)

$$x=-\frac{1}{2}i=-0.5i$$

$$x=\frac{1}{2}i=0.5i$$

Steps by Finding Square Root

Multiply x and x to get x^{2}.

$$2x^{2}\times 4+2=0$$

Multiply 2 and 4 to get 8.

$$8x^{2}+2=0$$

Subtract 2 from both sides. Anything subtracted from zero gives its negation.

$$8x^{2}=-2$$

Divide both sides by 8.

$$x^{2}=\frac{-2}{8}$$

Reduce the fraction \frac{-2}{8} to lowest terms by extracting and canceling out 2.

$$x^{2}=-\frac{1}{4}$$

The equation is now solved.

$$x=\frac{1}{2}i x=-\frac{1}{2}i$$

Steps Using the Quadratic Formula

Multiply x and x to get x^{2}.

$$2x^{2}\times 4+2=0$$

Multiply 2 and 4 to get 8.

$$8x^{2}+2=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 8 for a, 0 for b, and 2 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\times 8\times 2}}{2\times 8}$$

Square 0.

$$x=\frac{0±\sqrt{-4\times 8\times 2}}{2\times 8}$$

Multiply -4 times 8.

$$x=\frac{0±\sqrt{-32\times 2}}{2\times 8}$$

Multiply -32 times 2.

$$x=\frac{0±\sqrt{-64}}{2\times 8}$$

Take the square root of -64.

$$x=\frac{0±8i}{2\times 8}$$

Multiply 2 times 8.

$$x=\frac{0±8i}{16}$$

Now solve the equation x=\frac{0±8i}{16} when ± is plus.

$$x=\frac{1}{2}i$$

Now solve the equation x=\frac{0±8i}{16} when ± is minus.

$$x=-\frac{1}{2}i$$

The equation is now solved.

$$x=\frac{1}{2}i x=-\frac{1}{2}i$$